x^2+2x+65=15

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Solution for x^2+2x+65=15 equation: 



x^2+2x+65=15

We move all terms to the left:

x^2+2x+65-(15)=0

We add all the numbers together, and all the variables

x^2+2x+50=0

a = 1; b = 2; c = +50;
Δ = b2-4ac
Δ = 22-4·1·50
Δ = -196
Delta is less than zero, so there is no solution for the equation

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